Several small programming questions (array de-weight, get the most characters in the string)

1. Write a method to remove the repeating elements of an array:

Method one: normal for loop nesting;

1 functionRemovesame (arr) {2 Console.log (arr);3          for(vari=0, len = arr.length; i<len; i++){4              for(varj=i+1; j<len-i; J + +){5                 if(Arr[i] = = =Arr[j]) {6Arr.splice (Arr[j], 1);//Delete If duplicate elements are detected7j--;//move forward one index to prevent missing certain elements when there are multiple repeating elements8                 }9             }Ten         } One Console.log (arr); A         returnarr; -     } -      the     vararr = [1,2,3,3,3,3,3,4,4]; -Removesame (arr);

Method Two: Using for...in to remove weight;

1 functionRemovesame (arr) {2             varobj = {};3             varNEWARR = [];4             varkey;5 6              for(vari=0; i<arr.length; i++){7Key =Arr[i];8                 if(Obj[key]) {9Obj[key] = 0;//if the object is not added, it is assigned a value of 0;Ten}Else{ OneObj[key] = 0;//if the object is added (that is, duplicate elements appear), it is overwritten with the original property, guaranteeing only one property name in the array; A                 }; -             }; -  the              for(Keyinchobj) { -Newarr.push (key);//adds attributes from the removed object to the new array -             }; -  + Console.log (NEWARR); -}

Method Three: Use IndexOf () (IndexOf can return the index position of the element in the array);

1 functionOnlyone (arr) {2         varArr1=[];//array to hold the removed heavy elements3          for(vari=0;i<arr.length;i++){4             if(Arr1.indexof (Arr[i]) ==-1) {//whether the first element of ARR has been saved in arr1, if saved, skipped (that is, duplicate elements are not in the array); Push the current item into the array5 Arr1.push (Arr[i]);6             }7         }8         returnarr1;9}

2. Determine the most frequently occurring characters in a string, and count the number of times:

1 functionGetmaxletter () {2     varobj={};//Save the characters and occurrences of the split3     4      for(varI=0, L=str.length, K; i<l; i++){5K = Str.charat (i);//extracts the characters from a string6         if(Obj[k]) {7obj[k]++;//The index of the character as the value of the object, or + + if it has occurred8}Else{9Obj[k] = 1;//If none of the elements in the object is assigned a value of 1, indicating that 1 occurrencesTen         } One     } A console.log (obj); -      -     varm = 0;//Maximum number of occurrences the     varMyarr = [];//the maximum number of characters that are used to hold the same amount in a string -      -      for(varKinchobj) {//for in iterates over the property values in the object (that is, the individual characters) -         if(Obj[k] >= m) {//if there is greater than the maximum value, the value is re-assigned +             if(Obj[k] >m) {     -Myarr = [];  +             } AMyarr.push (k);//if equal, the same character is stored in the array atm = Obj[k];//number of fetches -         } -     } -Console.log (' Most occurrences of the characters are: ' + Myarr + ', occurrences: ' +m); - } -  in varstr = "Hello worlllllddddddd"; -Getmaxletter (str);

Several small programming questions (array de-weight, get the most characters in the string)