T001 a+b (with common standard input and output)

International practice OJ The first way is A+b bar. It is said that in order to adapt to various OJ compilers. Sorted out some common standard input and output

1#include <stdio.h>//a set of data roll rough2 3 intMain ()4 {5     intA, B;6scanf"%d%d", &a, &B);7printf"%d\n", A +B);8     return 0;9 }Ten  One#include <stdio.h>//multiple sets of data do not end A  - intMain () - { the     intA, B; -      while(SCANF ("%d%d", &a, &b)! =EOF) { -printf"%d\n", A +B); -     } +     return 0; - } +  A#include <stdio.h>//Number of Groups + multiple sets of data at  - intMain () - { -     intA, B, N, I; -scanf"%d", &n); -      for(i=0; i<n;i++){ inscanf"%d%d", &a, &B); -printf"%d\n", A +B); to     } +     return 0; - } the  *#include <stdio.h>//with 0 End $ Panax Notoginseng intMain () - { the     intA, B, N, I; +      while(SCANF ("%d%d", &a, &b) && (a!=0&&b!=0)){ Aprintf"%d\n", A +B); the     } +     return 0; - } $  $#include <stdio.h>//0 0 End -  - intMain () the { -     intA, B, N, I;Wuyi      while(SCANF ("%d%d", &a, &b) && (a!=0|| b!=0)){ theprintf"%d\n", A +B); -     } Wu     return 0; -}

　　

T001 a+b (with common standard input and output)