The method of calculating time difference in Java _java

This article illustrates the method of calculating the time difference in Java. Share to everyone for your reference. Specifically as follows:

Let's say it's 2004-03-26 13:31:40.
The past is: 2004-01-02 11:30:24
To get two date difference, the form of difference is: xx days xx hours xx minutes xx seconds

Method One:

DateFormat df = new SimpleDateFormat ("Yyyy-mm-dd HH:mm:ss");
Try
{
  Date D1 = Df.parse ("2004-03-26 13:31:40");
  Date D2 = Df.parse ("2004-01-02 11:30:24");
  Long diff = d1.gettime ()-d2.gettime ();
  Long days = diff/(1000 *);
}
catch (Exception e)
{
}

Method Two:

SimpleDateFormat df = new SimpleDateFormat ("Yyyy-mm-dd HH:mm:ss");
Java.util.Date now = Df.parse ("2004-03-26 13:31:40");
Java.util.Date date=df.parse ("2004-01-02 11:30:24");
Long L=now.gettime ()-date.gettime ();
Long day=l/(24*60*60*1000);
Long hour= (l/(60*60*1000)-day*24);
Long min= ((l/(60*1000))-day*24*60-hour*60);
Long s= (l/1000-day*24*60*60-hour*60*60-min*60);
System.out.println ("" +day+ "Day" +hour+ "hour" +min+ "minute" +s+ "seconds");

Method Three:

SimpleDateFormat dfs = new SimpleDateFormat ("Yyyy-mm-dd HH:mm:ss");
Java.util.Date begin=dfs.parse ("2004-01-02 11:30:24");
Java.util.Date end = Dfs.parse ("2004-03-26 13:31:40");
Long between= (End.gettime ()-begin.gettime ())/1000;
divided by 1000 to convert to a second
long day1=between/(24*3600);
Long hour1=between% (24*3600)/3600;
Long minute1=between%3600/60;
Long second1=between%60/60;
System.out.println ("" +day1+ "Day" +hour1+ "hour" +minute1+ "minute" +second1+ "seconds");

I hope this article will help you with your Java programming.