The Strip,lstrip,rstrip of Python myths

Recently, when working with data, I want to remove the ")" symbol at the beginning of a string, so use Targetstr.lstrip (")") to find

When the processed data is inserted into the database, there will be an error encoding, so the online search for this post. The cause of the above coding error problem occurs

My understanding of the Lstrip function is wrong, the authoritative explanation is as follows:

Str.lstrip ([chars])

Return a copy of the string with leading characters removed. The chars argument is a string

Specifying the set of characters to be removed. If omitted or None, the chars argument

defaults to removing whitespace. The chars argument is not a prefix; Rather, all combinations

Of its values is stripped:

". Lstrip ()" www.example.com  '. Lstrip ('cmowz. ' )'example.com'

Strip, Lstrip, Rstrip, the situation is the same, the most important thing is to pay attention to:

The parameter chars is a collection, not prefix (all combinations of characters in the chars collection are deleted)

So I analyze the situation where I went wrong:

>>> A =")">>> B ="(">>>a'\xef\xbc\x89'>>>b'\xef\xbc\x88'>>>Len (a)3>>>A.lstrip (b)'\x89'>>>B.lstrip (a)'\x88'>>> Targetstr =") Ask Python master: (a)">>>PrintTargetstr.lstrip (a) Ask a Python expert: (a)>>> Print  targetstr.lstrip (b)? Ask a Python expert: (a) >>> Targetstr ="(1) Ask Python master: (a)">>> Print  targetstr.lstrip (a)? 1) Ask Python master: (a) >>>PrintTargetstr.lstrip (b)1) Ask Python master: (a)

So the solution I'm using is as follows,

Method 1:

>>> Targetstr =") Ask Python master: (a)">>> targetstr = targetstr[3:]ifTargetstr.find (")") = = 0ElseTargetstr>>>Printtargetstr for a Python master: (a)>>> Targetstr ="(1) Ask Python master: (a)">>> targetstr = targetstr[3:]ifTargetstr.find (")") = = 0ElseTargetstr>>>PrintTargetstr (1) Ask Python master: (a)

Method 2:

>>> Len (U")")1>>> targetstr = u") Ask Python master: (a)">>>Printtargetstr) Ask Python master: (a)>>>Targetstru'\uff09\u6c42\u6559python\u9ad8\u624b\uff1a\uff08\u4e00\uff09'>>> targetstr = Targetstr.lstrip (u")")>>>Targetstru'\u6c42\u6559python\u9ad8\u624b\uff1a\uff08\u4e00\uff09'>>>Printtargetstr for a Python master: (a)>>> targetstr = u"(1) Ask Python master: (a)">>>PrintTargetstr (1) Ask Python master: (a)>>>Targetstru'\uff081\uff09\u6c42\u6559python\u9ad8\u624b\uff1a\uff08\u4e00\uff09'>>> targetstr = Targetstr.lstrip (u")")>>>Targetstru'\uff081\uff09\u6c42\u6559python\u9ad8\u624b\uff1a\uff08\u4e00\uff09'>>>PrintTargetstr (1) Ask Python master: (a)

If you have a better way, be sure to tell me:)

In addition, from this post I also learned another point:

>>> c = Int ("\t22\n")>>> c22

References:
Ask a Python expert: a simple question, Lstrip function cutting error

The Strip,lstrip,rstrip of Python myths