To find the maximum number of consecutive bits

Title Description

Function: To find a byte number corresponding to the binary number 1 of the maximum consecutive number, such as 3 of the binary 00000011, the maximum continuous 2 1
Input: A byte-type number
Output: None
Returns: The maximum number of consecutive digits in the corresponding binary number 1

Enter a description

Enter a byte number

Output description

The number of consecutive 1 after the output turns into binary

Input sample　　

3

Output sample

2

Problem analysis

You can find the maximum number of consecutive 1 for the right edge of the digital edge.

Test code

1#include <stdio.h>2 3 intMainvoid)4 {5     intnum, Count =0, max =0;6 7      while(SCANF ("%d", &num)! =EOF)8     {9Count = max =0;Ten          while(num) One         { A             if(Num &1) -             { -count++; theMax = (Count > Max)?Count:max; -             } -             Else -             { +Count =0; -             } +Num >>=1; A         } atprintf"%d\n", max); -     } -     return 0; -}

To find the maximum number of consecutive bits