UVa10651 (memory-based search)

Question:

For a string composed of-and o, you can change "-oo" to "o --", and "oo-" to "-- o ", the minimum number of o Records.

 

State compression, memory-based search

Code:

 

 #include <stdio.h>  #include <string.h>  #define len 12  #define min(a,b) (((a)<(b)) ?(a):(b))  int d[1<<13]; int dp(int n) {     int i, t;     if(d[n]!=-1) return d[n];     d[n] = 0;     for(i=0; i<len; i++)         if(n&(1<<i))             d[n]++;     for(i=0; i<len-2; i++)     {         t = n;         if( (t&(1<<i)) && (t&(1<<(i+1))) && !(t&(1<<(i+2))) )         {             t &=~(1<<i);             t &=~(1<<(i+1));             t |=1<<(i+2);             d[n] = min(d[n],dp(t));         }         if( !(t&(1<<i)) && (t&(1<<(i+1))) && (t&(1<<(i+2))) )         {             t &=~(1<<(i+1));             t &=~(1<<(i+2));             t |=1<<i;             d[n] = min(d[n],dp(t));         }     }     return d[n]; } int main() {     int T, i, n;     char str[20];     scanf("%d",&T);     while(T--)     {         scanf("%s",str);         n = 0;         for(i=0; i<len; i++)             if(str[i]=='o')                 n ^=1<<i;         memset(d,-1,sizeof(d));         printf("%d\n", dp(n));     }     return 0; } #include <stdio.h>#include <string.h>#define len 12#define min(a,b) (((a)<(b)) ?(a):(b))int d[1<<13];int dp(int n){    int i, t;    if(d[n]!=-1) return d[n];    d[n] = 0;    for(i=0; i<len; i++)        if(n&(1<<i))            d[n]++;    for(i=0; i<len-2; i++)    {        t = n;        if( (t&(1<<i)) && (t&(1<<(i+1))) && !(t&(1<<(i+2))) )        {            t &=~(1<<i);            t &=~(1<<(i+1));            t |=1<<(i+2);            d[n] = min(d[n],dp(t));        }        if( !(t&(1<<i)) && (t&(1<<(i+1))) && (t&(1<<(i+2))) )        {            t &=~(1<<(i+1));            t &=~(1<<(i+2));            t |=1<<i;            d[n] = min(d[n],dp(t));        }    }    return d[n];}int main(){    int T, i, n;    char str[20];    scanf("%d",&T);    while(T--)    {        scanf("%s",str);        n = 0;        for(i=0; i<len; i++)            if(str[i]=='o')                n ^=1<<i;        memset(d,-1,sizeof(d));        printf("%d\n", dp(n));    }    return 0;}