Title Link: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5518
For an upcoming programming contest, Edward, the headmaster of Marjar University, was forming a Two-man team from N Stu Dents of his university.
Edward knows the skill level of each student. He has found so if students with skill level A B and form a team, the skill level of the team A would be ⊙ B , Where⊕means bitwise exclusive OR. A team would play well if and only if the skill level of the team are greater than the skill level of each team member (i.e. A⊙ B > max{ A , B }).
Edward wants to form a team that'll play well in the contest. Please tell him the possible number of such teams. Teams is considered different if there was at least one different team member.
Input
There is multiple test cases. The first line of input contains an integer indicating the number of the T test cases. For each test case:
The first line contains an integer N (2 <= N <= 100000), which indicates the number of student. The next line contains N positive integers separated by spaces. The ith integer denotes the skill level of ith student. Every integer would not exceed 109.
Output
For each case, print the answer on one line.
Sample Input
231 2 351 2 3 4 5
Sample Output
16
Author:LIN, Xi
Source:The 12th Zhejiang Provincial Collegiate Programming Contest
Test instructions
Given the number of n, each time the number of two, asked how many kinds of election method can make the selected two number of the difference or value than the two number of the largest number of the larger.
That isz = x^y, z > Max (x, y).
Ps:
For a number, if we turn 0 of the binary representation of X into 1, and 0 is the same, then the new value obtained is certainly larger than X.
The code is as follows:
#include <cstdio> #include <cstring> #include <cmath> #define MAXN 100017int A[MAXN], c[maxn];void cal ( int m) {int L = 31; while (l >= 0) {if (M & (1<<l)) {c[l]++; return; } l--; } return; int main () {int t; int n; scanf ("%d", &t); while (t--) {memset (c,0,sizeof (c)); scanf ("%d", &n); for (int i = 0; i < n; i++) {scanf ("%d", &a[i]); Cal (A[i]); } int ans = 0; for (int i = 0; i < n; i++) {int l = 31; while (l >= 0) {if ((1<<l) & A[i])//Find the position of the front one { Break } l--; } while (l >= 0) {if (!) ( (1<<l) & A[i]) {ans+=c[l]; } l--; } } printf ("%d\n", ans); } return 0;}
ZOJ 3870 Team Formation (bitwise operations)