1:A+B Problem

標籤：blog   http   java   os   strong   io   

總時間限制: 

1000ms 

記憶體限制: 

65536kB

描述

Calculate a + b

輸入

Two integer a,,b (0 ≤ a,b ≤ 10)

輸出

Output a + b

範例輸入

1 2

範例輸出

3

提示

Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use ‘scanf‘ in C or ‘cin‘ in C++ to read from stdin, and use ‘printf‘ in C or ‘cout‘ in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so. 

Here is a sample solution for problem 1000 using C++/G++:
[cpp] view plaincopyprint? 

1. #include <iostream>  
2. using namespace std;  
3. int  main()  
4. {  
5.     int a,b;  
6.     cin >> a >> b;  
7.     cout << a+b << endl;  
8.     return 0;  
9. }  

It‘s important that the return type of main() must be int when you use G++/GCC,or you may get compile error.

Here is a sample solution for problem 1000 using C/GCC:
[cpp] view plaincopyprint? 

1. #include <stdio.h>  
2.   
3. int main()  
4. {  
5.     int a,b;  
6.     scanf("%d %d",&a, &b);  
7.     printf("%d\n",a+b);  
8.     return 0;  
9. }  

Here is a sample solution for problem 1000 using PASCAL:
[plain] view plaincopyprint? 

1. program p1000(Input,Output);   
2. var   
3.   a,b:Integer;   
4. begin   
5.    Readln(a,b);   
6.    Writeln(a+b);   
7. end.  

Here is a sample solution for problem 1000 using JAVA:

Now java compiler is jdk 1.5, next is program for 1000
[java] view plaincopyprint? 

1. import java.io.*;  
2. import java.util.*;  
3. public class Main  
4. {  
5.             public static void main(String args[]) throws Exception  
6.             {  
7.                     Scanner cin=new Scanner(System.in);  
8.                     int a=cin.nextInt(),b=cin.nextInt();  
9.                     System.out.println(a+b);  
10.             }  
11. }  

Old program for jdk 1.4
[java] view plaincopyprint? 

1. import java.io.*;  
2. import java.util.*;  
3.   
4. public class Main  
5. {  
6.     public static void main (String args[]) throws Exception  
7.     {  
8.         BufferedReader stdin =   
9.             new BufferedReader(  
10.                 new InputStreamReader(System.in));  
11.   
12.         String line = stdin.readLine();  
13.         StringTokenizer st = new StringTokenizer(line);  
14.         int a = Integer.parseInt(st.nextToken());  
15.         int b = Integer.parseInt(st.nextToken());  
16.         System.out.println(a+b);  
17.     }  
18. }  

原始碼：

[java] view plaincopyprint? 

1. <pre name="code" class="cpp">int main(void)  
2. {  
3.     int a, b;  
4.     scanf("%d%d", &a, &b);  
5.     printf("%d", a+b);  
6.     return 0;  
7. }