2012 #3 Arcane Numbers

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Arcane Numbers 1Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64uSubmit Status Practice HDU 4320

Description

Vance and Shackler like playing games. One day, they are playing a game called "arcane numbers". The game is pretty simple, Vance writes down a finite decimal under base A, and then Shackler translates it under base B. If Shackler can translate it into a finite decimal, he wins, else it will be Vance’s win. Now given A and B, please help Vance to determine whether he will win or not. Note that they are playing this game using a mystery language so that A and B may be up to 10^12. 

Input

The first line contains a single integer T, the number of test cases. 
For each case, there’s a single line contains A and B.  

Output

For each case, output “NO” if Vance will win the game. Otherwise, print “YES”. See Sample Output for more details. 

Sample Input

35 52 31000 2000  

Sample Output

Case #1: YESCase #2: NOCase #3: YES

 1 #include <stdio.h> 2 #include <string.h> 3 #include <algorithm> 4 using namespace std; 5  6 long long gcd(long long a,long long b)  7 {  8     if(a<b)  9         return gcd(b,a); 10     else if(b==0) 11         return a; 12     else13         return gcd(b,a%b); 14 }15 16 int main()17 {18     int T,ca=1;19     long long A,B;20     int i,j,k,flg;21     scanf("%d",&T);22     while(T--)23     {24         scanf("%I64d %I64d",&A,&B);25         long long C=gcd(A,B),D;26         A=A/C,B=B/C;27         flg=1;28         if(B>1)29         {30             while(1)31             {32                 if(B==1)33                     break;34                 D=gcd(B,C);35                 if(D==1)36                 {37                     flg=0;38                     break;39                 }40                 B=B/D;41             }42         }43         if(A>1)44         {45             while(1)46             {47                 if(A==1)48                     break;49                 D=gcd(A,C);50                 if(D==1)51                 {52                     flg=0;53                     break;54                 }55                 A=A/D;56             }57         }58         if(flg==1)59             printf("Case #%d: YES\n",ca);60         else61             printf("Case #%d: NO\n",ca);62         ca++;63     }64     return 0;65 }

View Code

 

2012 #3 Arcane Numbers