88Merge Sorted Array

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標籤:leetcode

88 Merge Sorted Array

連結:https://leetcode.com/problems/merge-sorted-array/
問題描述:
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

Hide Tags Array Two Pointers
Hide Similar Problems (E) Merge Two Sorted Lists

歸併兩個數組,要注意的是輸入中m和n兩個數字指定了兩個數組中的前m個數字和n個數字有效。這一題也可以用二分法排序。

class Solution {public:    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {        while(nums1.size()>m)            nums1.pop_back();        while(nums2.size()>n)            nums2.pop_back();        nums1.insert(nums1.begin(),nums2.begin(),nums2.end());        sort(nums1.begin(),nums1.end());    }};

也可以用歸併排序。

class Solution {public:    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {        while(nums1.size()>m)            nums1.pop_back();        while(nums2.size()>n)            nums2.pop_back();        vector<int>::iterator it1=nums1.begin();        vector<int>::iterator it2=nums2.begin();        while(it1!=nums1.end()&&it2!=nums2.end())          if(*it1>=*it2)              nums1.insert(it1,*it2++);           else              it1++;        while(it2!=nums2.end())            nums1.push_back(*it2++);    }};

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88Merge Sorted Array

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