Access中參數錯誤的問題

來源:互聯網
上載者:User

string sql = "update tb_type set typename=@typename,describe2=@describe2 where id=@id";
           OleDbParameter[] parameters = {
                 
                    new OleDbParameter("@typename", OleDbType.VarChar,50),
                    new OleDbParameter("@describe2", OleDbType.VarChar,50),
                    new OleDbParameter("@id", OleDbType.Integer,4)};
          

         
           parameters[0].Value = model.typename;
           parameters[1].Value = model.describe2;
           parameters[2].Value = model.id;

 

 

在access中居然要求順序依次對應,今天這個錯誤做的,哎

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