標籤:
1.首先下載json所以依賴的包, Json-lib 最新版 json-lib-2.3-jdk15.jar,其官方網站是:http://json-lib.sourceforge.net/可以直接download,細心的你會發現其網站頁面裡面有提示它還需要其他包:
Json-lib requires (at least) the following dependencies in your classpath:
•jakarta commons-lang 2.4
•jakarta commons-beanutils 1.7.0
•jakarta commons-collections 3.2
•jakarta commons-logging 1.1.1
•ezmorph 1.0.6
分別是:
http://commons.apache.org/lang/
http://commons.apache.org/beanutils/
http://commons.apache.org/collections/
http://commons.apache.org/logging/
http://ezmorph.sourceforge.net/
2.首先先見一個小web項目
User類:
package com.json;public class User { String username; String password; public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } }
servlet :
package com.json;import java.io.IOException;import java.io.PrintWriter;import java.util.ArrayList;import java.util.List;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import net.sf.json.JSONArray;public class TestJson extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { doPost(request,response); } public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html"); String str= =request.getParameter("name");//得到ajax傳遞過來的paramater PrintWriter out = response.getWriter(); List list = new ArrayList();//傳遞List Map m=new HashMap();//傳遞Map User u1=new User(); u1.setUsername("zah"); u1.setPassword("123"); User u2=new User(); u2.setUsername("ztf"); u2.setPassword("456"); list.add(u1); //添加User對象 list.add(u2); //添加User對象 m.put("u1", u1); m.put("u2", u2); JSONArray jsonArray2 = JSONArray.fromObject( list ); //把java數組轉化成轉化成json對象 JSONObject jo=JSONObject.fromObject(m); //轉化Map對象 out.print(jsonArray2);//返給ajax請求 out.print(jo);//返給ajax請求 }}
ajax實現:
<script type="text/javascript" src="js/jquery.js"></script><script type="text/javascript"> function test(){ $.ajax({ type:"POST", //請求方式 url:"testjson", //請求路徑 cache: false, data:"name=zah", //傳參 dataType: ‘json‘, //傳回值類型 success:function(json){ alert(json[0].username+" " json[0].password); //彈出返回過來的List對象 } }); }</script>
<body> <input type="button" name="b" value="測試" onclick=test()></body>
輸出:zah 123
訪問Map的話直接把返回函數改成如下即可:
success:function(json){ alert(json.u1.username)}
ajax+json+java