ASP.NET中將資料作為XML資料發送 使用 Request.InputStream 接收

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將資料作為XML資料發送,例如:
public void PostXml(string url, string xml)
{
byte[] bytes = Encoding.UTF8.GetBytes(xml);
HttpWebRequest request = (HttpWebRequest) WebRequest.Create(url);
request.Method = "POST";
request.ContentLength = bytes.Length;
request.ContentType = "text/xml";
using (Stream requestStream = request.GetRequestStream()) {
requestStream.Write(bytes, 0, bytes.Length);
}HttpWebResponse response = (HttpWebResponse) request.GetResponse();
if (response.StatusCode != HttpStatusCode.OK) {
string message = String.Format("POST failed. Received HTTP {0}",
response.StatusCode);
throw new ApplicationException(message);
}
}
接收端通過Request.InputStream讀取:
byte[] byts = new byte[Request.InputStream.Length];
Request.InputStream.Read(byts,0,byts.Length);
string req = System.Text.Encoding.Default.GetString(byts);
req = Server.UrlDecode(req);
對於完整的XML資料,可以:
xmlDoc = new XmlDocument();
xmlDoc.load(Request.InputStream);

ASP.NET中將資料作為XML資料發送 使用 Request.InputStream 接收