C++ 多重繼承

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標籤:多重繼承   c++   

參考於上一篇虛函數,多重繼承也分為有無虛函數覆蓋的問題; 在虛表存在著不同的情況

多重繼承(無虛函數覆蓋)


參考虛表:


這裡子類的虛函數地址,添加到第一個繼承的父類的虛表裡面 此外虛表中的 . 地區代表是否 還存在虛表 1 表示還存在虛表,0則表示最後一個虛表;

代碼如下:

#include <iostream>using namespace std;class Base1{    public:        virtual void f()        {            cout << " Base1 :: f() " << endl;        }        virtual void g()        {            cout << " Base1 :: g() " << endl;        }        virtual void h()        {            cout << " Base1 :: h() " << endl;        }};class Base2{    public:        virtual void f()        {            cout << " Base2 :: f() " << endl;        }        virtual void g()        {            cout << " Base2 :: g() " << endl;        }        virtual void h()        {            cout << " Base2 :: h() " << endl;        }};class Base3{    public:        virtual void f()        {            cout << " Base3 :: f() " << endl;        }        virtual void g()        {            cout << " Base3 :: g() " << endl;        }        virtual void h()        {            cout << " Base3 :: h() " << endl;        }};class Derived:public Base2,public Base1,public Base3{    public:        virtual void f1()        {            cout << " Derived:: f1() " << endl;        }        virtual void g1()        {            cout << "Derived:: g1() " << endl;        }};typedef void(*Fun)(void);//函數指標 存放地址 知道地址 調用函數int main(){    Derived d;    Fun pFun = NULL;    int** pVtab = (int**)(&d);    //Base1's virtual table    pFun = (Fun)pVtab[0][0];    pFun();    pFun = (Fun)pVtab[0][1];    pFun();    pFun = (Fun)pVtab[0][2];    pFun();    pFun = (Fun)pVtab[0][3];    pFun();    pFun = (Fun)pVtab[0][4];    pFun();    cout << pFun << endl;    //Base2's virtual table    pFun = (Fun)pVtab[1][0];    pFun();    pFun = (Fun)pVtab[1][1];    pFun();    pFun = (Fun)pVtab[1][2];    pFun();    pFun = (Fun)pVtab[1][3];    cout << pFun << endl;    //Base3's virtual table    pFun = (Fun)pVtab[2][0];    pFun();    pFun = (Fun)pVtab[2][1];    pFun();    pFun = (Fun)pVtab[2][2];    pFun();    pFun = (Fun)pVtab[2][3];    cout << pFun << endl;    return 0;}
輸出的結果 對應於前面的 虛表:先繼承Base2 先輸出(繼承順序) 



有虛函數的覆蓋:


此時對應的虛表:


測試代碼:

#include <iostream>using namespace std;class Base1{    public:        virtual void f()        {            cout << " Base1 :: f() " << endl;        }        virtual void g()        {            cout << " Base1 :: g() " << endl;        }        virtual void h()        {            cout << " Base1 :: h() " << endl;        }};class Base2{    public:        virtual void f()        {            cout << " Base2 :: f() " << endl;        }        virtual void g()        {            cout << " Base2 :: g() " << endl;        }        virtual void h()        {            cout << " Base2 :: h() " << endl;        }};class Base3{    public:        virtual void f()        {            cout << " Base3 :: f() " << endl;        }        virtual void g()        {            cout << " Base3 :: g() " << endl;        }        virtual void h()        {            cout << " Base3 :: h() " << endl;        }};class Derived:public Base2,public Base1,public Base3{    public:        virtual void f()        {            cout << " Derived:: f1() " << endl;        }        virtual void g1()        {            cout << "Derived:: g1() " << endl;        }};typedef void(*Fun)(void);//函數指標 存放地址 知道地址 調用函數int main(){    Derived d;    Fun pFun = NULL;    int** pVtab = (int**)(&d);    //Base1's virtual table    pFun = (Fun)pVtab[0][0];    pFun();    pFun = (Fun)pVtab[0][1];    pFun();    pFun = (Fun)pVtab[0][2];    pFun();    pFun = (Fun)pVtab[0][3];    pFun();    pFun = (Fun)pVtab[0][4];    //pFun();    cout << pFun << endl;    //Base2's virtual table    pFun = (Fun)pVtab[1][0];    pFun();    pFun = (Fun)pVtab[1][1];    pFun();    pFun = (Fun)pVtab[1][2];    pFun();    pFun = (Fun)pVtab[1][3];    cout << pFun << endl;    //Base3's virtual table    pFun = (Fun)pVtab[2][0];    pFun();    pFun = (Fun)pVtab[2][1];    pFun();    pFun = (Fun)pVtab[2][2];    pFun();    pFun = (Fun)pVtab[2][3];    cout << pFun << endl;    return 0;}
運行結果 如下:


父類的f()函數的位置被子類的f()覆蓋。對應於上面的虛表;


C++ 多重繼承

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