函數式線段樹。
利用了可持久化的思想,降低時間和空間複雜度。
#include<cstdio>#include<cstring>#include<algorithm>using namespace std;const int maxn=2000005;int n,Q,a[maxn],b[maxn];struct node{ int L,R,sum; node* ch[2]; void maintain(){ sum=ch[0]->sum+ch[1]->sum; }} *rt[maxn], base[maxn], *len=base, nil, *null=&nil;node* newnode(int L,int R,int sum){ len->L=L; len->R=R; len->sum=sum; len->ch[0]=len->ch[1]=null; return len++;}node* build(int L,int R){ node* p=newnode(L,R,0); if(L==R) return p; int mid=(L+R)>>1; p->ch[0]=build(L,mid); p->ch[1]=build(mid+1,R); p->maintain(); return p;}node* Updata(node* pre,int val){ node* p=newnode(pre->L,pre->R,pre->sum); p->ch[0]=pre->ch[0]; p->ch[1]=pre->ch[1]; if(p->L==p->R){ p->sum++; return p; } int mid=(p->L+p->R)>>1; if(val<=mid) p->ch[0]=Updata(p->ch[0],val); else p->ch[1]=Updata(p->ch[1],val); p->maintain(); return p;}int Query(node* tl,node* tr,int K){ if(tl->L==tl->R) return b[tl->L]; int tem=tr->ch[0]->sum-tl->ch[0]->sum; if(K<=tem) return Query(tl->ch[0],tr->ch[0],K); return Query(tl->ch[1],tr->ch[1],K-tem);}int find(int x){ return lower_bound(b+1,b+1+b[0],x)-b; }int main(){ freopen("poj2104.in","r",stdin); freopen("poj2104.out","w",stdout); scanf("%d%d",&n,&Q); for(int i=1;i<=n;i++) scanf("%d",&a[i]), b[++b[0]]=a[i]; sort(b+1,b+1+b[0]); b[0]=unique(b+1,b+1+b[0])-(b+1); rt[0]=build(1,b[0]); for(int i=1;i<=n;i++) rt[i]=Updata(rt[i-1],find(a[i])); while(Q--){ int x,y,z; scanf("%d%d%d",&x,&y,&z); printf("%d\n",Query(rt[x-1],rt[y],z)); } return 0;}