PHP下使用CURL方式POST資料至API介面的代碼_PHP教程

來源:互聯網
上載者:User
其實,也比較簡單,上代碼:
複製代碼 代碼如下:

$url = 'http://127.0.0.1/test.php';//POST指向的連結
$data = array(
'access_token'=>'thekeyvalue'
);

$json_data = postData($url, $data);
$array = json_decode($json_data,true);
echo '
';print_r($array);      

function postData($url, $data)
{
$ch = curl_init();
$timeout = 300;
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_REFERER, "http://www.jb51.net/"); //構造來路
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
$handles = curl_exec($ch);
curl_close($ch);
return $handles;
}
?>

http://www.bkjia.com/PHPjc/326623.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/326623.htmlTechArticle其實,也比較簡單,上代碼: 複製代碼 代碼如下: ?php $url = 'http://127.0.0.1/test.php';//POST指向的連結 $data = array( 'access_token'='thekeyvalue' ); $jso...

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