Codeforces Beta Round #96 (Div. 2)

C. Turing Tapetime limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

INTERCAL is the oldest of esoteric programming languages. One of its many weird features is the method of character-based output, known as Turing Tape method. It converts an array of unsigned 8-bit integers into a sequence of characters to print, using the
following method.

The integers of the array are processed one by one, starting from the first. Processing i-th element of the array is done in three steps:

1. The 8-bit binary notation of the ASCII-code of the previous printed character is reversed. When the first element of the array is processed, the result of this step is considered to be 0.

2. The i-th element of the array is subtracted from the result of the previous step modulo 256.

3. The binary notation of the result of the previous step is reversed again to produce ASCII-code of the i-th character to be printed.

You are given the text printed using this method. Restore the array used to produce this text.

<p< p="" style="font-family: verdana, arial, sans-serif; font-size: 14px; line-height: 21px; "><p< p="">

Input

<p< p="">

The input will consist of a single line text which contains the message printed using the described method. String text will
contain between 1 and 100 characters, inclusive. ASCII-code of each character of text will be between 32 (space) and 126 (tilde), inclusive.

<p< p=""><p< p="">

Output

<p< p="">

Output the initial array, which was used to produce text, one integer per line.

<p< p=""><p< p="">

Sample test(s)

<p< p=""><p< p="">

input

Hello, World!

output

23810811206419448262441682416162

<p< p=""><p< p="">

Note

<p< p="">

Let's have a closer look at the beginning of the example. The first character is "H" with ASCII-code 72 = 01001000_{2.
Its reverse is 000100102 = 18, and this number should become the result of the second step of processing. The result of the first
step is considered to be 0, so the first element of the array has to be (0 - 18) mod 256 = 238,
where a mod b is the remainder of division of a by b.}

1. #include<iostream>using namespace std;int main(){    char str[200];    int num, i, j, k;    int pre = 0;    char temp[10];    cin.getline(str,200,'\n');    for ( i = 0; str[i] != 0; i++ )    {        num = str[i]; j = 0;        while ( num != 0  )        {            k = num % 2;            temp[j++] = k + '0';            num = ( num - k ) / 2;        }        while ( j < 8 ) temp[j++] = '0';        temp[j] = '\0';        for ( j = 0; j < 8; j++ )            num += (temp[j] -'0') << (7-j) ;        //cout << "##" << temp << ' ' << num << endl;        k = (pre - num ) % 256;        if ( k < 0 ) k += 256;        cout << k << endl;        pre = num;    }    return 0;}