Codeforces Round #448 (Div. 2) B. XK Segments【進位思維/排序】

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B. XK Segmentstime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard output

While Vasya finished eating his piece of pizza, the lesson has already started. For being late for the lesson, the teacher suggested Vasya to solve one interesting problem. Vasya has an array a and integer x. He should find the number of different ordered pairs of indexes (i, j)such that ai ≤ aj and there are exactly k integers y such that ai ≤ y ≤ aj and y is divisible byx.

In this problem it is meant that pair (i, j) is equal to (j, i) only if i is equal to j. For example pair (1, 2) is not the same as (2, 1).

Input

The first line contains 3 integers n, x, k (1 ≤ n ≤ 105, 1 ≤ x ≤ 109, 0 ≤ k ≤ 109), where n is the size of the array a and x and k are numbers from the statement.

The second line contains n integers ai (1 ≤ ai ≤ 109) — the elements of the array a.

Output

Print one integer — the answer to the problem.

Examplesinput

4 2 1
1 3 5 7

output

3

input

4 2 0
5 3 1 7

output

4

input

5 3 1
3 3 3 3 3

output

25

Note

In first sample there are only three suitable pairs of indexes — (1, 2), (2, 3), (3, 4).

In second sample there are four suitable pairs of indexes(1, 1), (2, 2), (3, 3), (4, 4).

In third sample every pair (i, j) is suitable, so the answer is 5 * 5 = 25.

【題意】：find the number of different ordered pairs of indexes (i, j) such that ai ≤ aj and there are exactly k integers y such that ai ≤ y ≤ aj and y is divisible by x.

y is divisible by x.（y被x整除）

比如12/4=3,我們就可以說12被4整除,4整除12

A可被B整除，表示A是B的倍數
A可整除B，表示B是A 的倍數

輸入 n, x, k  an

找到不同有序下標對(i,j) 滿足ai ≤ aj 並且剛好有k個整數 y( ai ≤ y ≤ aj )，y%x==0的數量。

【分析】：

Codeforces Round #448 (Div. 2) B. XK Segments【進位思維/排序】