android 雙擊退出

android 雙擊退出

@Overridepublic boolean onKeyDown(int keyCode, KeyEvent event) {if (keyCode == KeyEvent.KEYCODE_BACK) {if(!exitBy2Click(HomeActivity.this)){return false;} // 調用雙擊退出函數}return super.onKeyDown(keyCode, event);}private long time;private boolean exitBy2Click(final Context context) {if(System.currentTimeMillis()-time>2000){//大於2秒Toast.makeText(context, "再按一下退出應用", Toast.LENGTH_SHORT).show();time = System.currentTimeMillis();Handler handler = new Handler();handler.postDelayed(new Runnable() {@Overridepublic void run() {time = 0;}}, 2000);return false;}else{//兩秒內。退出應用return true;}}

貌似沒有什麼bug 吧