【練習01】 簡單題（1）1003

#include<iostream>#include<string>#include <iomanip>using namespace std;int main(){int n, m;int temp;char ch[101];string s;cin>>n;double count_line;double count_case;for(int i = 0; i < n; i++){//處理每個casecount_case = 0;cin>>m;for(int j = 0; j < m; j++){//處理case中的每一行count_line = 0;cin>>s;strcpy(ch, s.c_str());for(int k = 0; ch[k] != '\0'; k++){//處理每一行中的每個字元if(ch[k] == '-'){continue;}else{if(ch[k+1] == '-' || ch[k+1] == '\0'){temp = ch[k] - 48;count_line += temp;}else{temp = (ch[k] - 48) * 10 + (ch[k + 1] - 48);count_line += temp;k++;}}}if(j == 0){count_case = count_line;}else{count_case = (count_case * count_line) / (count_case + count_line);}}cout.setf(ios::fixed,ios::floatfield);   // floatfield set to fixedcout.precision(2);cout<<count_case<<endl; }}