# -*- coding: cp936 -*-
'''
檔案比較演算法:
演算法模型參見:
# 參考文章:http://blog.csdn.net/clariones/archive/2006/11/19/1396880.aspx
# http://blog.csdn.net/clariones/archive/2006/11/24/1412394.aspx
1.確定最大匹配率
2.確定最優匹配路徑
'''
left = 'ABCACADF'
right = 'BCXCADFESBABCACA'
all = []
# 建立矩陣,行數與列數均為left,right的長度+1,並將所有元素置0
for i in range(len(left) + 1):
all.append([])
for j in range(len(right) + 1):
all[i].append(0)
##for i in all:
## print i
# 比較left與right的值,相同的將矩陣中對應元素置1
for l in range(len(left)):
for r in range(len(right)):
if left[l] == right[r]:
all[l][r] = 1
##print '*'* 10
##for i in all:
## print i
# 計算最大匹配數
for i in range(len(left) - 1,-1,-1):
for j in range(len(right) - 1,-1,-1):
all[i][j] = max(all[i][j+1],all[i+1][j+1]+ all[i][j],all[i+1][j])
print '*' * 20
for i in all:
print i
# 計算最短路徑
for j in range(len(right) - 1,-1,-1):
for i in range(len(left) - 1,-1,-1):
if left[i] == right[j]:
all[i][j] = all[i + 1][j + 1] + 1
else:
if all[i + 1][j] >= all[i][j + 1]:
all[i][j] = all[i + 1][j]
else:
all[i][j] = all[i][j+1] + 1
print '*' * 20
for i in all:
print i