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SQL:重複資料刪除資料,只保留一條用SQL語句,刪除掉重複項只保留一條在幾千條記錄裡,存在著些相同的記錄,如何能用SQL語句,刪除掉重複的呢
1、尋找表中多餘的重複記錄,重複記錄是根據單個欄位(peopleId)來判斷
select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
2、刪除表中多餘的重複記錄,重複記錄是根據單個欄位(peopleId)來判斷,只留有rowid最小的記錄
delete from people where peopleName in (select peopleName from people group by peopleName having count(peopleName) > 1) and peopleId not in (select min(peopleId) from people group by peopleName having count(peopleName)>1)
3、尋找表中多餘的重複記錄(多個欄位)
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、刪除表中多餘的重複記錄(多個欄位),只留有rowid最小的記錄
delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5、尋找表中多餘的重複記錄(多個欄位),不包含rowid最小的記錄
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
6.消除一個欄位的左邊的第一位:
update tableName set [Title]=Right([Title],(len([Title])-1)) where Title like ‘村%‘
7.消除一個欄位的右邊的第一位:
update tableName set [Title]=left([Title],(len([Title])-1)) where Title like ‘%村‘
8.假刪除表中多餘的重複記錄(多個欄位),不包含rowid最小的記錄
update vitae set ispass=-1 where peopleId in (select peopleId from vitae group by peopleId,seq having count(*) > 1) and seq in (select seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
本文轉自:http://www.cnblogs.com/huangw/archive/2012/06/04/2534676.html
【轉】SQL重複資料刪除記錄,只保留其中一條