golang捕獲ctrl+c退出程式

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在golang當中如何捕獲ctrl+c命令，讓程式有序的的退出？

首先測試一段golang代碼,捕獲SIGINT和SIGKILL

c := make(chan os.Signal, 1)signal.Notify(c, os.Interrupt, os.Kill)s := <-cfmt.Println("Got signal:", s)

在多goroutines當中如何退出？我們假設有一個生產者，一個消費者，這個時候應該讓生產者去捕獲訊息，關閉channel，生產者退出；消費者感知到channel關閉，消費者退出。

package mainimport (    "time"    "fmt"    "os"    "os/signal"    "sync")var c chan os.Signalvar msgQueue chan *stringvar wg sync.WaitGroupfunc Producer(){    i := 0    LOOP:    for{        select {        case s := <-c:            fmt.Println()            fmt.Println("Producer | get", s)            break LOOP        default:        }        i ++        s := fmt.Sprintf("work-%d", i)        fmt.Println("Producer | produce", s)        msgQueue <- &s        time.Sleep(500 * time.Millisecond)    }    close(msgQueue)    fmt.Println("Producer | close channel, exit")    wg.Done()}func Consumer(){    for m := range msgQueue{        if m != nil{            fmt.Println("Consumer | consume", *m)        }else{            fmt.Println("Consumer | channel closed")            break        }    }    fmt.Println("Consumer | exit")    wg.Done()}func main(){    c = make(chan os.Signal, 1)    msgQueue = make(chan *string, 1000)    signal.Notify(c, os.Interrupt, os.Kill)    //pruducer    wg.Add(1)    go Producer()    //consumer    wg.Add(1)    go Consumer()    wg.Wait()}

運行結果：

Producer | produce work-1Consumer | consume work-1Producer | produce work-2Consumer | consume work-2Producer | produce work-3Consumer | consume work-3Producer | produce work-4Consumer | consume work-4Producer | get interruptProducer | close channel, exitConsumer | exit

參考：
1. http://www.oschina.net/translate/golang-graceful-stop?lang=eng