golang(Go語言) byte/[]byte 與 二進位形式字串 互轉

這是一個建立於 的文章，其中的資訊可能已經有所發展或是發生改變。

效果

把某個位元組或位元組數群組轉換成字串01的形式，一個位元組用8個”0”或”1”字元表示。比如：
byte(3) –> “00000011”
[]byte{1,2,3} –> “[00000001 00000010 00000011]”
“[00000011 10000000]” –> []byte{0x3, 0x80}

開源庫 biu

實際上我已經將其封裝到一個開源庫了(biu)，其中的一個功能就能達到上述效果：

//byte/[]byte -> stringbs := []byte{1, 2, 3}s := biu.BytesToBinaryString(bs)fmt.Println(s) //[00000001 00000010 00000011]fmt.Println(biu.ByteToBinaryString(byte(3))) //00000011//string -> []bytes := "[00000011 10000000]"bs := biu.BinaryStringToBytes(s)fmt.Printf("%#v\n", bs) //[]byte{0x3, 0x80}

代碼實現

const (    zero  = byte('0')    one   = byte('1')    lsb   = byte('[') // left square brackets    rsb   = byte(']') // right square brackets    space = byte(' '))var uint8arr [8]uint8// ErrBadStringFormat represents a error of input string's format is illegal .var ErrBadStringFormat = errors.New("bad string format")// ErrEmptyString represents a error of empty input string.var ErrEmptyString = errors.New("empty string")func init() {    uint8arr[0] = 128    uint8arr[1] = 64    uint8arr[2] = 32    uint8arr[3] = 16    uint8arr[4] = 8    uint8arr[5] = 4    uint8arr[6] = 2    uint8arr[7] = 1}// append bytes of string in binary format.func appendBinaryString(bs []byte, b byte) []byte {    var a byte    for i := 0; i < 8; i++ {        a = b        b <<= 1        b >>= 1        switch a {        case b:            bs = append(bs, zero)        default:            bs = append(bs, one)        }        b <<= 1    }    return bs}// ByteToBinaryString get the string in binary format of a byte or uint8.func ByteToBinaryString(b byte) string {    buf := make([]byte, 0, 8)    buf = appendBinaryString(buf, b)    return string(buf)}// BytesToBinaryString get the string in binary format of a []byte or []int8.func BytesToBinaryString(bs []byte) string {    l := len(bs)    bl := l*8 + l + 1    buf := make([]byte, 0, bl)    buf = append(buf, lsb)    for _, b := range bs {        buf = appendBinaryString(buf, b)        buf = append(buf, space)    }    buf[bl-1] = rsb    return string(buf)}// regex for delete useless string which is going to be in binary format.var rbDel = regexp.MustCompile(`[^01]`)// BinaryStringToBytes get the binary bytes according to the// input string which is in binary format.func BinaryStringToBytes(s string) (bs []byte) {    if len(s) == 0 {        panic(ErrEmptyString)    }    s = rbDel.ReplaceAllString(s, "")    l := len(s)    if l == 0 {        panic(ErrBadStringFormat)    }    mo := l % 8    l /= 8    if mo != 0 {        l++    }    bs = make([]byte, 0, l)    mo = 8 - mo    var n uint8    for i, b := range []byte(s) {        m := (i + mo) % 8        switch b {        case one:            n += uint8arr[m]        }        if m == 7 {            bs = append(bs, n)            n = 0        }    }    return}