杭電1002

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#include <iostream>#include <string>#include <string.h>#include <stdlib.h>using namespace std;int main(){int a[1002];int b[1002];int n;char aa[1002];char bb[1002];cin>>n;int line = 1;while (line <= n){cin>>aa>>bb;memset(a, 0, sizeof(a));       //不要寫入程式碼，採用sizeof，因為是int是4位元組，之前自己給自己埋了個坑，寫成1002。。。memset(b, 0, sizeof(b));int strLenA = strlen(aa);for (int i = 0; i < strLenA; i++)    //數組逆轉存入{a[i] = aa[strLenA - 1 - i] - ‘0‘;}int strLenB = strlen(bb);for (int j = 0; j < strLenB; j++){b[j] = bb[strLenB - 1 - j] - ‘0‘;}int maxLen = strLenA > strLenB ? strLenA : strLenB;for (int k = 0; k < maxLen; k++)   //先處理高位{a[k+1] += (a[k] + b[k]) / 10;a[k] = (a[k]+ b[k]) % 10;}cout<<"Case "<<line<<":"<<endl;cout<<aa<<" + "<<bb<<" = ";if (a[maxLen] > 0)                //判斷最高位是否有進位cout<<a[maxLen];for (int kk = maxLen - 1; kk >= 0; kk--)cout<<a[kk];cout<<endl;if (line < n)                  //注意最後一個案例不要多輸出空行cout<<endl;line++;}return 0;}

　　

杭電1002