HDU-1039-Easier Done Than Said?(Java && 沒用Regex是我的遺憾.....)

標籤：acm   java   水題   學習Regex   pattern和matcher   

Easier Done Than Said? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 9845    Accepted Submission(s): 4784


Problem DescriptionPassword security is a tricky thing. Users prefer simple passwords that are easy to remember (like buddy), but such passwords are often insecure. Some sites use random computer-generated passwords (like xvtpzyo), but users have a hard time remembering them and sometimes leave them written on notes stuck to their computer. One potential solution is to generate "pronounceable" passwords that are relatively secure but still easy to remember.

FnordCom is developing such a password generator. You work in the quality control department, and it‘s your job to test the generator and make sure that the passwords are acceptable. To be acceptable, a password must satisfy these three rules:

It must contain at least one vowel.

It cannot contain three consecutive vowels or three consecutive consonants.

It cannot contain two consecutive occurrences of the same letter, except for ‘ee‘ or ‘oo‘.

(For the purposes of this problem, the vowels are ‘a‘, ‘e‘, ‘i‘, ‘o‘, and ‘u‘; all other letters are consonants.) Note that these rules are not perfect; there are many common/pronounceable words that are not acceptable.
 
InputThe input consists of one or more potential passwords, one per line, followed by a line containing only the word ‘end‘ that signals the end of the file. Each password is at least one and at most twenty letters long and consists only of lowercase letters.
 
OutputFor each password, output whether or not it is acceptable, using the precise format shown in the example.
 
Sample Input

atvptouibontreszoggaxwiinqeephouctuhend

 
Sample Output

<a> is acceptable.<tv> is not acceptable.<ptoui> is not acceptable.<bontres> is not acceptable.<zoggax> is not acceptable.<wiinq> is not acceptable.<eep> is acceptable.<houctuh> is acceptable.

 
SourceMid-Central USA 2000



 
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題目說了很多廢話，說什麼設定密碼是什麼複雜的事情啦，設定過於簡單也不行，沒有規律又不好記憶，總之它的意思是說，你要滿足它設定密碼的三個條件，滿足則給你acceptable否則給你not acceptable。(三個條件在注釋裡面......)
因為題目過於水，而且英文也較好理解(題意還是比較清晰明了的),這裡不做過多解釋,Java水過......

import java.io.*;import java.util.*;public class Main{public static void main(String[] args){// TODO Auto-generated method stubScanner input = new Scanner(System.in);while (input.hasNext()){boolean flag1 = false, flag2 = true, flag3 = true;String str = input.next();if (str.endsWith("end"))break;char c[] = str.toCharArray();// 第一個條件：必須包含至少一個母音字母for (int i = 0; i < c.length; i++){if (c[i] == 'a' || c[i] == 'e' || c[i] == 'i' || c[i] == 'o'|| c[i] == 'u'){flag1 = true;break;}}// 第二個條件：不能包含三個連續的母音字母或者三個連續的輔音字母int a = 0, b = 0;for (int i = 0; i < c.length; i++){if (c[i] == 'a' || c[i] == 'e' || c[i] == 'i' || c[i] == 'o'|| c[i] == 'u'){a++;if (a >= 3){flag2 = false;}b = 0;} else{b++;if (b >= 3){flag2 = false;}a = 0;}}// 第三個條件：不能包含兩個連續相同的字母，除了'ee'和'oo'這兩種情況除外int i, j = 0;for (i = 1; i < c.length; i++, j++){if (c[i] == c[j]){if (c[i] == 'e' || c[i] == 'o')continue;else{flag3 = false;break;}}}if (flag1 && flag2 && flag3){System.out.println("<" + str + "> is acceptable.");} else{System.out.println("<" + str + "> is not acceptable.");}}}}

另外圍觀王維大牛RegexPattern和Matcher（本來想用這題來練Regex的.....但是我還是沒搞懂啊）

import java.util.Scanner;import java.util.regex.Matcher;import java.util.regex.Pattern;public class Main {public static void main(String[] args) throws Exception {Scanner cin = new Scanner(System.in);while (cin.hasNext()) {String str = cin.next();if(str.equals("end"))break;Pattern p1 = Pattern.compile("[aeiou]{3}|[^aeiou]{3}");Pattern p2 = Pattern.compile("([a-df-np-z])\\1");Pattern p3 = Pattern.compile("[aeiou]+");Matcher m = p1.matcher(str);boolean flag = false;if(!m.find()){m = p2.matcher(str);if(!m.find()){m = p3.matcher(str);if(m.find())flag = true;}}if(flag)System.out.println("<"+str+"> is acceptable.");elseSystem.out.println("<"+str+"> is not acceptable.");}cin.close();}}

 

HDU-1039-Easier Done Than Said?(Java && 沒用Regex是我的遺憾.....)