hdu 1039 Easier Done Than Said?

/*水題。        處理字串        滿足的三個條件：        1.至少有一個母音字母        2.不能有連續三個輔音字母或者母音字母        3.不能有連續兩個相同字母，"ee"和"oo"除外*/#include <stdio.h>#include <string.h>#define len n#define maxn 25int  main(){char str[maxn];while(scanf("%s",str)){int len=strlen(str);if(len==3 && str[0]=='e' && str[1]=='n' && str[2]=='d')return 0;int flag=1;int num_a,num_b,count=0;for(int i=0;i<n;i++)if(str[i]=='a'||str[i]=='e'||str[i]=='i' || str[i]=='o' || str[i]=='u')count++;if(count==0){printf("<%s> is not acceptable.\n",str);continue;}for(int i=1;i<n;i++){if(str[i]==str[i-1] && (str[i]!='e' && str[i]!='o')){printf("<%s> is not acceptable.\n",str);flag=0;break;}}if(flag==0)continue;for(int i=0; i<n; i++){if(str[i]=='a'||str[i]=='e'||str[i]=='i' || str[i]=='o' || str[i]=='u'){if(flag==0)break;num_a=1;int j=i+1;while(str[j]=='a'||str[j]=='e'||str[j]=='i' || str[j]=='o' || str[j]=='u' && j<n){j++;num_a++;if(num_a>=3){flag=0;break;}}                i=j-1;}else{if(flag==0)break;num_b=1;int j=i+1;while(str[j]!='a' && str[j]!='e' && str[j]!='i' && str[j]!='o' && str[j]!='u' && j<n){j++;num_b++;if(num_b>=3){flag=0;break;}}                i=j-1;}//printf("%d %d",i,num_a,num_b);}if(flag==1)printf("<%s> is acceptable.\n",str);elseprintf("<%s> is not acceptable.\n",str);}}