HDU-1316 How Many Fibs? Java

來源:互聯網
上載者:User

  首先把100位長的斐波那契數全部計算出來,然後遍曆計數,很暴力啊!

  代碼如下:

import java.math.BigInteger;import java.util.Scanner;public class Main {    public static void main(String[] args) {        Scanner in = new Scanner(System.in);        BigInteger[] a = new BigInteger[1000];        a[1] = BigInteger.ONE;        a[2] = BigInteger.ONE.add( BigInteger.ONE );        a[3] = a[1].add(a[2]);        int i;        for (i = 3; i <= 500; ++i) {            a[i] = a[i - 1].add(a[i - 2]);        }        BigInteger l, r;        while (in.hasNextBigInteger()) {            int cnt = 0;            l = in.nextBigInteger();            r = in.nextBigInteger();            if (BigInteger.ZERO.equals(l) && BigInteger.ZERO.equals(r)) {                break;            }            for (int j = 1; j <= 500; ++j) {                if (l.compareTo(a[j]) <= 0 && r.compareTo(a[j]) >= 0) {                    cnt++;                }            }            System.out.println(cnt);        }    }}

  

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