HDU 2054 A == B ?

A == B ?

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 49760 Accepted Submission(s): 7654

Problem DescriptionGive you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Inputeach test case contains two numbers A and B.

Outputfor each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input

1 22 23 34 3

Sample Output

NOYESYESNO

 

 

總結：

           題目和簡單，但是要考慮和多情況:

            1. 全部為0的情況

            2.有加號或減號的情況

            3.浮點數（刪掉小數點前面的0和小數點後面的0）

例子：       

            1:  +00.0和-0 、+0和-0 、00.00 和0  等等全部為0 的情況；
            2:  001.1和1.10 、000.01 和0.010 、+000.01 和-0.010  等等

            3:  01.10 和01.1  、+01.10 和-01.1等等

            4:  001.1 和1.1、-001.1 和+1.1  等等

 

import java.util.*;import java.io.*;public class Main {public static void main(String[] args) {Scanner sc=new Scanner(new BufferedInputStream(System.in));while(sc.hasNext()){String s1=sc.next();String s2=sc.next();s1=fun(s1);s2=fun(s2);if(s1.equals(s2))System.out.println("YES");else System.out.println("NO");}}public static String fun(String s){boolean b=true;//處理全部為0的情況for(int i=0;i<s.length();i++){if(s.charAt(i)!='0'&&s.charAt(i)!='.'&&s.charAt(i)!='+'&&s.charAt(i)!='-'){b=false;break;}}if(b==true) return "0";//處理 加號或減號的情況StringBuffer bu=new StringBuffer(s);if(s.charAt(0)!='+'&&s.charAt(0)!='-'){for(int i=0;i<bu.length();i++){if(bu.charAt(i)=='0'){bu.replace(i, i+1, "");i--;}else break;}}else{for(int i=1;i<bu.length();i++){if(bu.charAt(i)=='0'){bu.replace(i, i+1, "");i--;}else break;}}//處理浮點數（刪掉小數點後面的0）if(s.contains(".")){bu.reverse();for(int i=0;i<bu.length();i++){if(bu.charAt(i)=='0'){bu.replace(i, i+1, "");i--;}else break;}int m=bu.indexOf(".");bu.replace(m, m+1, "");bu.reverse();}return bu.toString();}}