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Couple doubi
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 607 Accepted Submission(s): 435
Problem DescriptionDouBiXp has a girlfriend named DouBiNan.One day they felt very boring and decided to play some games. The rule of this game is as following. There are k balls on the desk. Every ball has a value and the value of ith (i=1,2,...,k) ball is 1^i+2^i+...+(p-1)^i (mod p). Number p is a prime number that is chosen by DouBiXp and his girlfriend. And then they take balls in turn and DouBiNan first. After all the balls are token, they compare the sum of values with the other ,and the person who get larger sum will win the game. You should print “YES” if DouBiNan will win the game. Otherwise you should print “NO”.
InputMultiply Test Cases.
In the first line there are two Integers k and p(1<k,p<2^31).
OutputFor each line, output an integer, as described above.
Sample Input
2 320 3
Sample Output
YESNO
AuthorFZU
Source2014 Multi-University Training Contest 1
題解:水平有點渣,比賽時打表看規律寫的。
#include <iostream>#include <cstdio>using namespace std;int main(){ int k,p; while(cin>>k>>p) { if(p) if(k/(p-1)%2==0) cout<<"NO"<<endl; else cout<<"YES"<<endl; } return 0;}