HDU A + B Again

A + B Again

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 11804 Accepted Submission(s): 5152

Problem DescriptionThere must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

InputThe input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

OutputFor each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

+A -A+1A 121A -9-1A -121A -AA

Sample Output

02C11-2C-90

總結:   Long.parseLong(s,16);將16進位的字串轉化為十進位

           Long.toString(sum,16)將一個十進位數字轉換為一個個十六進位的字串

           toUpperCase();  將字串中的小寫字母轉換為大寫字母

 

import java.util.*;import java.io.*;import java.math.BigInteger;public class Main {public static void main(String[] args) {Scanner sc=new Scanner(new BufferedInputStream(System.in));while(sc.hasNext()){String  s1=sc.next();String s2=sc.next();long num1=fun(s1);long num2=fun(s2);long sum=num1+num2;String str=Long.toString(sum,16).toUpperCase();//將一個十進位數字轉換為一個個十六進位的字串，將字串中的小寫字母轉換為大寫字母System.out.println(str);}}public static long fun(String s){if(s.charAt(0)=='+')s=s.substring(1);return Long.parseLong(s,16);//將16進位的字串轉化為十進位}}