HDU1051 Wooden Sticks

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Wooden Sticks

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 9125    Accepted Submission(s): 3729

Problem DescriptionThere is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to
prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:

(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.

You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is
a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2). 

InputThe input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1<=n<=5000, that represents the number of wooden
sticks in the test case, and the second line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one
or more spaces. 

OutputThe output should contain the minimum setup time in minutes, one per line. 

Sample Input

3 5 4 9 5 2 2 1 3 5 1 4 3 2 2 1 1 2 2 3 1 3 2 2 3 1
 

Sample Output

213
 

SourceAsia 2001, Taejon (South Korea)

#include<stdio.h>#include<algorithm>using namespace std;struct node   //儲存棍子屬性,長,重,是否訪問 {    int l;    int w;    int v;}str[5002];bool cmp(node a,node b)   //按長度、重量從小到大排序{    if(a.l==b.l)        return a.w<b.w;    return a.l<b.l;}int main(){    int t,n;    int tim;    int i,j;    scanf("%d",&t);    while(t--)    {        tim=0;        scanf("%d",&n);        for(i=0;i<n;i++)        {            scanf("%d%d",&str[i].l,&str[i].w);            str[i].v=0;        }        sort(str,str+n,cmp);   //排序        int l,w;        for(i=0;i<n;i++)     //選取第i根木棒(排序後)為加工時的第一根木棒        {            if(str[i].v==0)            {                l=str[i].l;                w=str[i].w;                str[i].v=1;                tim++;            }            for(j=i+1;j<n;j++)            {                if(str[j].v==0&&str[j].l>=l&&str[j].w>=w)                {                    l=str[j].l;                    w=str[j].w;                    str[j].v=1;                }            }        }        printf("%d\n",tim);    }    return 0;}

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