Hoj 1005 利用矩陣計算線性遞推式

來源:互聯網
上載者:User
#include <stdio.h>void matrix_mul(int (*a)[2],int (*b)[2]);//a = a * bvoid matrix_matrix(int n,int (*a)[2],int (*b)[2]);int main (){    int a,b,n,fn;    int f[2][2],ans[2][2];        while (1){    scanf("%d%d%d",&a,&b,&n);    if (a == 0 && b == 0 && n == 0 )    break;    f[0][0] = a;f[0][1] = 1;    f[1][0] = b;f[1][1] = 0;    ans[0][0] = 1;ans[0][1] = 0;    ans[1][0] = 0;ans[1][1] = 1;        matrix_matrix(n - 2,ans,f);    fn = (ans[0][0] + ans[1][0]) % 7 ;    printf("%d\n",fn);    }    return 0;}void matrix_mul(int (*a)[2],int (*b)[2]){        int i[2][2];        i[0][0] = (a[0][0] * b[0][0] + a[0][1] * b[1][0]) % 7;        i[0][1] = (a[0][0] * b[0][1] + a[0][1] * b[1][1]) % 7;        i[1][0] = (a[1][0] * b[0][0] + a[1][1] * b[1][0]) % 7;        i[1][1] = (a[1][0] * b[0][1] + a[1][1] * b[1][1]) % 7;        a[0][0] = i[0][0];a[1][0] = i[1][0];        a[0][1] = i[0][1];a[1][1] = i[1][1];        //printf("%d %d\n%d %d\n\n",a[0][0],a[0][1],a[1][0],a[1][1]);}void matrix_matrix(int n,int (*ans)[2],int (*f)[2]){    while (n != 0){        if (n % 2 == 1)    matrix_mul(ans,f);        n = n / 2;        matrix_mul(f,f);    }}

 

聯繫我們

該頁面正文內容均來源於網絡整理,並不代表阿里雲官方的觀點,該頁面所提到的產品和服務也與阿里云無關,如果該頁面內容對您造成了困擾,歡迎寫郵件給我們,收到郵件我們將在5個工作日內處理。

如果您發現本社區中有涉嫌抄襲的內容,歡迎發送郵件至: info-contact@alibabacloud.com 進行舉報並提供相關證據,工作人員會在 5 個工作天內聯絡您,一經查實,本站將立刻刪除涉嫌侵權內容。

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.