財務部提出在EXCEL中輸入一個數字,可以自動轉換成英文。這樣可以節約他們很多重複勞動的時間。其實呢,這個問題不是我的職責範圍拉,不過好像同事有EXCEL的問題都會來問問我的,我覺得協助他們其實我自己也可以得到提高,所以我就研究了一下這個問題,發現其實通過自訂函數還是很容易解決的。
1.建立一個模組:
在SHEET上,右鍵-》查看代碼。選中“模組”-》插入模組。
2.寫代碼:
Option Explicit
Dim StrNO(19) As String
Dim Unit(8) As String
Dim StrTens(9) As String
Public Function NumberToString(Number As Double) As String
Dim Str As String, BeforePoint As String, AfterPoint As String, tmpStr As String
Dim Point As Integer
Dim nBit As Integer
Dim CurString As String
Dim nNumLen As Integer
Dim T As String
Call Init
Str = CStr(Round(Number, 2))
' Str = Number
If InStr(1, Str, ".") = 0 Then
BeforePoint = Str
AfterPoint = ""
Else
BeforePoint = Left(Str, InStr(1, Str, ".") - 1)
T = Right(Str, Len(Str) - InStr(1, Str, "."))
If Len(T) < 2 Then AfterPoint = Val(T) * 10
If Len(T) = 2 Then AfterPoint = Val(T)
If Len(T) > 2 Then AfterPoint = Val(Left(T, 2))
End If
If Len(BeforePoint) > 12 Then
NumberToString = "Too Big."
Exit Function
End If
Str = ""
Do While Len(BeforePoint) > 0
nNumLen = Len(BeforePoint)
If nNumLen Mod 3 = 0 Then
CurString = Left(BeforePoint, 3)
BeforePoint = Right(BeforePoint, nNumLen - 3)
Else
CurString = Left(BeforePoint, (nNumLen Mod 3))
BeforePoint = Right(BeforePoint, nNumLen - (nNumLen Mod 3))
End If
nBit = Len(BeforePoint) / 3
tmpStr = DecodeHundred(CurString)
If (BeforePoint = String(Len(BeforePoint), "0") Or nBit = 0) And Len(CurString) = 3 Then
If CInt(Left(CurString, 1)) <> 0 And CInt(Right(CurString, 2)) <> 0 Then
'tmpStr = Left(tmpStr, InStr(1, tmpStr, Unit(4)) + Len(Unit(4))) & Unit(8) & " " & Right(tmpStr, Len(tmpStr) - (InStr(1, tmpStr, Unit(4)) + Len(Unit(4))))
Else 'If CInt(Left(CurString, 1)) <> 0 And CInt(Right(CurString, 2)) = 0 Then
'tmpStr = Unit(8) & " " & tmpStr
End If
End If
If nBit = 0 Then
Str = Trim(Str & " " & tmpStr)
Else
Str = Trim(Str & " " & tmpStr & " " & Unit(nBit))
End If
If Left(Str, 3) = Unit(8) Then Str = Trim(Right(Str, Len(Str) - 3))
If BeforePoint = String(Len(BeforePoint), "0") Then Exit Do
'Debug.Print Str
Loop
BeforePoint = Str
If Len(AfterPoint) > 0 Then
AfterPoint = Unit(8) & " " & Unit(7) & " " & DecodeHundred(AfterPoint) & " " & Unit(5)
Else
AfterPoint = Unit(5)
End If
NumberToString = BeforePoint & " " & AfterPoint
End Function
Private Function DecodeHundred(HundredString As String) As String
Dim tmp As Integer
If Len(HundredString) > 0 And Len(HundredString) <= 3 Then
Select Case Len(HundredString)
Case 1
tmp = CInt(HundredString)
If tmp <> 0 Then DecodeHundred = StrNO(tmp)
Case 2
tmp = CInt(HundredString)
If tmp <> 0 Then
If (tmp < 20) Then
DecodeHundred = StrNO(tmp)
Else
If CInt(Right(HundredString, 1)) = 0 Then
DecodeHundred = StrTens(Int(tmp / 10))
Else
DecodeHundred = StrTens(Int(tmp / 10)) & "-" & StrNO(CInt(Right(HundredString, 1)))
End If
End If
End If
Case 3
If CInt(Left(HundredString, 1)) <> 0 Then
DecodeHundred = StrNO(CInt(Left(HundredString, 1))) & " " & Unit(4) & " " & DecodeHundred(Right(HundredString, 2))
Else
DecodeHundred = DecodeHundred(Right(HundredString, 2))
End If
Case Else
End Select
End If
End Function
Private Sub Init()
If StrNO(1) <> "One" Then
StrNO(1) = "One"
StrNO(2) = "Two"
StrNO(3) = "Three"
StrNO(4) = "Four"
StrNO(5) = "Five"
StrNO(6) = "Six"
StrNO(7) = "Seven"
StrNO(8) = "Eight"
StrNO(9) = "Nine"
StrNO(10) = "Ten"
StrNO(11) = "Eleven"
StrNO(12) = "Twelve"
StrNO(13) = "Thirteen"
StrNO(14) = "Fourteen"
StrNO(15) = "Fifteen"
StrNO(16) = "Sixteen"
StrNO(17) = "Seventeen"
StrNO(18) = "Eighteen"
StrNO(19) = "Nineteen"
StrTens(1) = "Ten"
StrTens(2) = "Twenty"
StrTens(3) = "Thirty"
StrTens(4) = "Forty"
StrTens(5) = "Fifty"
StrTens(6) = "Sixty"
StrTens(7) = "Seventy"
StrTens(8) = "Eighty"
StrTens(9) = "Ninety"
Unit(1) = "Thousand" '材熌
Unit(2) = "Million" '材熌
Unit(3) = "Billion" '材熌
Unit(4) = "Hundred"
Unit(5) = "Only"
Unit(6) = "Point"
Unit(7) = "Cents"
Unit(8) = "And"
End If
End Sub
儲存此代碼到本地
3.模組中已經定義了函數名稱:NumberToString
直接當作EXCEL本地函數使用,例如在A1=7,在B1中輸入=NumberToString(A1)就可以拉!很簡單的吧?