標籤:border 初始化順序 display pad 靜態代碼塊 ext com ide nal
方便查看初始化順序,使用了下面的列印類
public class Print {public Print(String str){System.out.println(str);}}
本文討論兩種情況下類的初始化順序,分別是單獨類的初始化,和有繼承關係的類的初始化
1.單獨類的初始化
以下面的代碼為例
public class Father {static {System.out.println("Father 靜態代碼塊");}public static Print fatherStaticPrint = new Print("Father 靜態變數");public Print fatherPrint = new Print("Father 非靜態變數");public Father(){System.out.println("Father 建構函式");}@Overrideprotected void finalize() throws Throwable {super.finalize();System.out.println("Father 解構函式");}}
在main函數當中初始化
public static void main(String args[]){Father father = new Father();System.runFinalizersOnExit(true); }
執行的結果如下
如果將Father類的靜態代碼塊和靜態變數位置變換一下,如下所示
public class Father {public static Print fatherStaticPrint = new Print("Father 靜態變數");static {System.out.println("Father 靜態代碼塊");}public Print fatherPrint = new Print("Father 非靜態變數");public Father(){System.out.println("Father 建構函式");}@Overrideprotected void finalize() throws Throwable {super.finalize();System.out.println("Father 解構函式");}}
那麼執行的結果就變成
因此可以得出結論:靜態代碼塊和靜態變數的優先順序是一樣的,誰排在前面就先初始化誰。
具體過程如所示:
2.有繼承關係的類的初始化
以下面的類為例
public class Son extends Father {static {System.out.println("Son 靜態代碼塊");}public static Print SonStaticPrint = new Print("Son 靜態變數");public Print SonPrint = new Print("Son 非靜態變數");public Son(){System.out.println("Son 建構函式");}@Overrideprotected void finalize() throws Throwable {super.finalize();System.out.println("Son 解構函式");}}
類Son繼承類Father,在Main函數當中初始化Son,執行結果如下
因此可以得出如下結論:
java類的初始化順序