java類的初始化順序

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標籤:border   初始化順序   display   pad   靜態代碼塊   ext   com   ide   nal   

方便查看初始化順序,使用了下面的列印類

public class Print {public Print(String str){System.out.println(str);}}

本文討論兩種情況下類的初始化順序,分別是單獨類的初始化,和有繼承關係的類的初始化

1.單獨類的初始化

以下面的代碼為例

public class Father {static {System.out.println("Father 靜態代碼塊");}public static Print fatherStaticPrint = new Print("Father 靜態變數");public Print fatherPrint = new Print("Father 非靜態變數");public Father(){System.out.println("Father 建構函式");}@Overrideprotected void finalize() throws Throwable {super.finalize();System.out.println("Father 解構函式");}}

在main函數當中初始化

public static void main(String args[]){Father father = new Father();System.runFinalizersOnExit(true); }

執行的結果如下

 

如果將Father類的靜態代碼塊和靜態變數位置變換一下,如下所示

public class Father {public static Print fatherStaticPrint = new Print("Father 靜態變數");static {System.out.println("Father 靜態代碼塊");}public Print fatherPrint = new Print("Father 非靜態變數");public Father(){System.out.println("Father 建構函式");}@Overrideprotected void finalize() throws Throwable {super.finalize();System.out.println("Father 解構函式");}}

那麼執行的結果就變成

因此可以得出結論:靜態代碼塊和靜態變數的優先順序是一樣的,誰排在前面就先初始化誰。

具體過程如所示:

 

2.有繼承關係的類的初始化

以下面的類為例

public class Son extends Father {static {System.out.println("Son 靜態代碼塊");}public static Print SonStaticPrint = new Print("Son 靜態變數");public Print SonPrint = new Print("Son 非靜態變數");public Son(){System.out.println("Son 建構函式");}@Overrideprotected void finalize() throws Throwable {super.finalize();System.out.println("Son 解構函式");}}

類Son繼承類Father,在Main函數當中初始化Son,執行結果如下

因此可以得出如下結論:

java類的初始化順序

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