Java數組,去掉重複值、增加、刪除數組元素的實現方法_java

如下所示：

import java.util.List;import java.util.ArrayList;import java.util.Set;import java.util.HashSet;public class lzwCode {public static void main(String [] args) {testA();System.out.println("===========================");testB();System.out.println("===========================");testC();}//去掉數組中重複的值public static void testA() {String [] str = {"Java", "C++", "Php", "C#", "Python", "C++", "Java"};for (String elementA:str ) {System.out.print(elementA + " ");}    List<String> list = new ArrayList<String>();for (int i=0; i<str.length; i++) {if(!list.contains(str[i])) {list.add(str[i]);}}/*Set<String> set = new HashSet<String>();for (int i=0; i<str.length; i++) {set.add(str[i]);}String[] newStr = set.toArray(new String[1]); */System.out.println();String[] newStr = list.toArray(new String[1]); //返回一個包含所有對象的指定類型的數組 for (String elementB:newStr ) {System.out.print(elementB + " ");}System.out.println();}//刪除數組中其中一個元素public static void testB() {String [] str = {"Java", "C++", "Php", "C#", "Python"};for (String elementA:str ) {System.out.print(elementA + " ");}//刪除phpList<String> list = new ArrayList<String>();for (int i=0; i<str.length; i++) {list.add(str[i]);}list.remove(2); //list.remove("Php") System.out.println();String[] newStr = list.toArray(new String[1]); //返回一個包含所有對象的指定類型的數組 for (String elementB:newStr ) {System.out.print(elementB + " ");}System.out.println();}//在數組中增加一個元素public static void testC() {String [] str = {"Java", "C++", "Php", "C#", "Python"};for (String elementA:str ) {System.out.print(elementA + " ");}//增加rubyList<String> list = new ArrayList<String>();for (int i=0; i<str.length; i++) {list.add(str[i]);}list.add(2, "ruby"); //list.add("ruby") System.out.println();String[] newStr = list.toArray(new String[1]); //返回一個包含所有對象的指定類型的數組 for (String elementB:newStr ) {System.out.print(elementB + " ");}System.out.println();}}

控制台結果：

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