來源:http://www.javaeye.com/topic/645596
不使用第三個變數完成兩個整數的交換,這個面試題大概大家都碰到過。如:
Java代碼
public class Person {
public static void main(String[] args) {
//利用加減法
int a = 10, b = 5;
a = a + b;
b = a - b;
a = a - b;
System.out.println("a=" + a + "\nb=" + b);
}
}
還有另外一種方法,且效率更快:
Java代碼
public class Person {
public static void main(String[] args) {
//利用一個數異或本身等於0和異或運算子合交換率
int a = 10, b = 5;
a = a ^ b;
b = a ^ b;
a = a ^ b;
System.out.println("a=" + a + "\nb=" + b);
}
}
當然以上兩種的演算法對應js中也支援,如下:
JS代碼
var a = 11,b = 22;
a = a + b;
b = a - b;
a = a - b;
console.log(a+'\n'+b)
或
JS代碼
var a = 11,b = 22;
a = a ^ b;
b = a ^ b;
a = a ^ b;
console.log(a+'\n'+b)
但如果兩個變數是物件類型,java(強型別)貌似無能為力了。js卻可以,實現方式還不少,如:
JS代碼
var a = {name:'jack'},b = {name:'tom'};
a = [a,b];
b = a[0];
a = a[1];
console.log(a.name+'\n'+b.name)
或
JS代碼
var a = {name:'jack'},b = {name:'tom'};
a = {a:a,b:b};
b = a.a;
a = a.b;
console.log(a.name+'\n'+b.name)
正是利用js動態類型(弱類型)系統及對象/數組直接量特性。其它強型別則不可以,編譯器會提示類型轉換錯誤。
資源:http://en.wikipedia.org/wiki/XOR_swap