jobdu 6 日期差值

題目描述：

有兩個日期，求兩個日期之間的天數，如果兩個日期是連續的我們規定他們之間的天數為兩天 輸入：

有多組資料，每組資料有兩行，分別表示兩個日期，形式為YYYYMMDD 輸出：

每組資料輸出一行，即日期差值 範例輸入：

2011041220110422

範例輸出：

11

 code1:

#include <stdio.h>int R[]={0,31,59,90,120,151,181,212,243,273,304,334};int calc(int date){int year=date/10000;int month=date%10000/100;int day=date%100;int r=R[month-1]+day;int x=0;for(int i=1;i<year;i++){if(((i%4==0)&&(i%100!=0))||(i%400==0))x++;}r+=x+(year-1)*365;if(((year%4==0)&&(year%100!=0))||(year%400==0)&&month>2)r++;return r;}int abs(int m){return m<0?-m:m;}int main(){int date1,date2;while(scanf("%d%d",&date1,&date2)!=EOF)printf("%d\n",abs(calc(date2)-calc(date1))+1);return 0;}

code2:

#include <stdio.h>#define ISYEAP(x) x%100!=0&&x%4==0||x%400==0?1:0int dayOfMonth[13][2]={0,0,31,31,28,29,31,31,30,30,31,31,30,30,31,31,31,31,30,30,31,31,30,30,31,31};struct Date{int Day;int Month;int Year;void nextDay(){Day++;if(Day>dayOfMonth[Month][ISYEAP(Year)]){Day=1;Month++;if(Month>12){Month=1;Year++;}}}};int buf[5001][13][32];int abs(int x){return x<0?-x:x;}int main(){Date tmp;tmp.Year=0;tmp.Month=1;tmp.Day=1;int cnt=0;while(tmp.Year!=5001){buf[tmp.Year][tmp.Month][tmp.Day]=cnt;tmp.nextDay();cnt++;}int y1,m1,d1;int y2,m2,d2;while(scanf("%4d%2d%2d",&y1,&m1,&d1)!=EOF){scanf("%4d%2d%2d",&y2,&m2,&d2);printf("%d\n",abs(buf[y2][m2][d2]-buf[y1][m1][d1])+1);}return 0;}