已知日期：2013-07-31 加12個月 3個月 1個月 得到相應的日期

已知日期：2013-07-31 加12個月 3個月 1個月 得到相應的日期

求大牛怎麼寫PHP代碼？

回複討論(解決方案)

$date1="2006-08-09";
echo date('Y-m-d',strtotime("$date1 +5 day")); //相應地,要增加月,年,將day改成month或year即可
?>
輸出結果：2006-08-14

+++++++++++++ 今天、昨天、明天 、上一周、下一周 +++++++++++++++

date_default_timezone_set('PRC'); //預設時區
echo "今天:",date("Y-m-d",time()),"
";
echo "昨天:",date("Y-m-d",strtotime("-1 day")), "
";
echo "明天:",date("Y-m-d",strtotime("+1 day")), "
";
echo "一周后:",date("Y-m-d",strtotime("+1 week")), "
";
echo "一周零兩天四小時兩秒後:",date("Y-m-d G:H:s",strtotime("+1 week 2 days 4 hours 2 seconds")), "
";
echo "下個星期四:",date("Y-m-d",strtotime("next Thursday")), "
";
echo "上個周一:".date("Y-m-d",strtotime("last Monday"))."
";
echo "一個月前:".date("Y-m-d",strtotime("last month"))."
";
echo "一個月後:".date("Y-m-d",strtotime("+1 month"))."
";
echo "十年後:".date("Y-m-d",strtotime("+10 year"))."
";

?>

$date1="2006-08-09";
echo date('Y-m-d',strtotime("$date1 +5 day")); //相應地,要增加月,年,將day改成month或year即可
?>
輸出結果：2006-08-14

+++++++++++++ 今天、昨天、明天 、上一周、下一周 +++++++++++++++

date_default_timezone_set('PRC'); //預設時區
echo "今天:",date("Y-m-d",time()),"
";
echo "昨天:",date("Y-m-d",strtotime("-1 day")), "
";
echo "明天:",date("Y-m-d",strtotime("+1 day")), "
";
echo "一周后:",date("Y-m-d",strtotime("+1 week")), "
";
echo "一周零兩天四小時兩秒後:",date("Y-m-d G:H:s",strtotime("+1 week 2 days 4 hours 2 seconds")), "
";
echo "下個星期四:",date("Y-m-d",strtotime("next Thursday")), "
";
echo "上個周一:".date("Y-m-d",strtotime("last Monday"))."
";
echo "一個月前:".date("Y-m-d",strtotime("last month"))."
";
echo "一個月後:".date("Y-m-d",strtotime("+1 month"))."
";
echo "十年後:".date("Y-m-d",strtotime("+10 year"))."
";

?>
這個不行。要加自然月，有的月分28天。有的31天

$s='2013-07-31';
echo date("Y-m-d",strtotime("$s+1 month"));

呵呵，想當然了

echo date("Y-m-d\n",strtotime("$s+7 month"));

得到 2014-03-03

select adddate('2013-07-31', INTERVAL 7 month)

得到 2014-02-28

顯然，php 的表現是不盡人意的

mktime其實也可以達到要求

$t = '2013-07-31';echo date("Y-m-d",mktime(0,0,0,date("m") + 12,date("d") , date("Y"))).'
';echo date("Y-m-d",mktime(0,0,0,date("m") + 3,date("d") , date("Y"))).'
';echo date("Y-m-d",mktime(0,0,0,date("m") + 1,date("d") , date("Y"))).'
';

結果:

2014-07-312013-10-312013-08-31

$t = '2013-07-31';echo date("Y-m-d",mktime(0,0,0,date("m") + 2,date("d") , date("Y")));

得 2013-10-01

最要不得的是：迴避矛盾

