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The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H NA P L S I I GY I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
ZigZag conversion 解題關鍵點在於尋找迴圈,(2 * nRows - 2)個字元構成一個迴圈。
1 string convert(string s, int nRows) 2 { 3 string *st = new string[nRows]; 4 int k, i; 5 if (nRows <= 1) 6 return s; 7 8 for (i = 0; i < s.length(); i++) 9 {10 k = i % (2 * nRows - 2);11 if (k >= (nRows - 1))12 st[2 * (nRows - 1) - k] += s[i];13 else14 st[k] += s[i];15 }16 17 s = "";18 for (i = 0; i < nRows; i++)19 s += st[i];20 21 return s;22 }
leetcode 6. ZigZag Conversion