leetcode-動態規劃

來源:互聯網
上載者:User

class Solution {public:    int minimumTotal(vector<vector<int>>& triangle) {        for(int i = triangle.size() - 2; i >= 0; --i){            for(int j = 0; j < i + 1; ++j){                triangle[i][j] += min(triangle[i + 1][j], triangle[i + 1][j + 1]);            }        }        return triangle[0][0];    }};

class Solution {public:    int maxSubArray(vector<int>& nums) {        int result = INT_MIN, f = 0;        for(int i = 0; i < nums.size(); ++i){            f = max(f + nums[i], nums[i]);            result = max(result, f);        }        return result;    }};


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