[LeetCode] Excel Sheet Column Title

來源:互聯網
上載者:User

標籤:

Given a positive integer, return its corresponding column title as appear in an Excel sheet.

For example:

    1 -> A    2 -> B    3 -> C    ...    26 -> Z    27 -> AA    28 -> AB 

Credits:
Special thanks to @ifanchu for adding this problem and creating all test cases.

 

Hide Tags MathHide Similar Problems (E) Excel Sheet Column Number 分析:本質上是10進位到26進位的轉換,但是 由於下標從1開始而不是從0開始,因此要減一操作。 1 --》A26--》Z 先取出餘數,然後將其轉換成字元A~Z,然後n= (n-1)/26,將26進位的數右移一位,然後從新做判斷。。 
#include <stdio.h>#include <stdlib.h>#include <iostream>#include <vector>#include <queue>#include <stack>#include <algorithm>using namespace std;void printArray(int *array, int size){    for(int i = 0; i < size; i++)        cout << array[i]<< "\t" ;    cout << endl;}void printVector(vector<int> array ){    for(int i = 0; i <array.size(); i++)        cout << array[i]<< "\t" ;    cout << endl;}class Solution {    public:        string convertToTitle(int n) {            string str;            int a = 0;            while(n)            {                   a = (n-1) % 26;                 str += char(a + ‘A‘);                n = (n-1)/26;            }               reverse(str.begin(), str.end());            return str;        }};#if 01 -> A2 -> B3 -> C...26 -> Z27 -> AA28 -> AB #endifint main(){    Solution sl;    cout << sl.convertToTitle(1) <<endl;    cout << sl.convertToTitle(100) <<endl;    cout << sl.convertToTitle(1000) <<endl;    cout << endl;    return 0;}

 

  

[LeetCode] Excel Sheet Column Title

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