【leetcode】Palindrome Number

Question：

Determine whether an integer is a palindrome. Do this without extra space.

Some hints:

Could negative integers be palindromes? (ie, -1)

If you are thinking of converting the integer to string, note the restriction of using extra space.

You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?

There is a more generic way of solving this problem.

Anwser 1：         

class Solution {public:    bool isPalindrome(int x) {        // Start typing your C/C++ solution below        // DO NOT write int main() function        if(x < 0) return false;                int div = 1;        while(x/10 >= div){     // get large division            div *= 10;        }                while(x > 9){            int high = x / div;     // left digit            int low = x % 10;       // right digit                        if(high != low){                return false;            }                        x = (x % div) / 10;     // get number between first and last            div /= 100;        }                return true;    }};

Anwser 2：      

class Solution {public:    bool check(int x, int &y) {        if (x == 0) return true;            if (check(x/10, y) && (x%10 == y%10)) {            y /= 10;            return true;        } else {            return false;        }    }    bool isPalindrome(int x) {        // Start typing your C/C++ solution below        // DO NOT write int main() function        if(x < 0) return false;                return check(x, x);    }};

參考推薦：

Palindrome Number