[LeetCode] Palindrome Partitioning

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Given a string s, partition s such that every substring of the partition is a palindrome.

Return all possible palindrome partitioning of s.

For example, given s = "aab", Return

  [    ["aa","b"],    ["a","a","b"]  ]
 注意下面的例子：                                                                          

Input:	"fff"
Expected:	[["f","f","f"],["f","ff"],["ff","f"],["fff"]]

 

class Solution {public:    vector<vector<string>> partition(string s) {        vector<vector<string>> res;        if(s.size()<1)            return res;        vector<string> partition;        addPalindrome(s,0,partition,res);        return res;    }private:    void addPalindrome(string s,int start,vector<string> &partition,vector<vector<string> >&res){        if(start == s.size()){            res.push_back(partition);            return;        }        for(int i = start+1;i<=s.size();i++){            string str = s.substr(start,i-start);            if(isPalindrome(str)){                partition.push_back(str);                addPalindrome(s,i,partition,res);                partition.pop_back();            }//end if        }//end for    }    bool isPalindrome(string str){        int left = 0;        int right = str.size()-1;        while(left<right){            if(str[left]!=str[right])                return false;            left++;            right--;        }//end while       return true;    }};

 方法：DFS！