[LeetCode] Rotate List

來源:互聯網
上載者:User

標籤:style   blog   color   io   for   div   amp   log   

Given a list, rotate the list to the right by k places, where k is non-negative.

For example: Given 1->2->3->4->5->NULL and k = 2, return 4->5->1->2->3->NULL.

/** * Definition for singly-linked list. * struct ListNode { *     int val; *     ListNode *next; *     ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public:    ListNode *rotateRight(ListNode *head, int k) {        if(k==0 || head==NULL || head->next == NULL)            return head;        int len=0;        ListNode *p = head;        while(p){            len++;            p = p->next;        }        while(len<k){           k -= len;        }        ListNode *Pfast = head,*Pslow =head,*h = head;        int i;        for(i=0;Pfast!=NULL && i<k+1;i++){            Pfast = Pfast->next;        }                while(Pfast!=NULL){            Pfast = Pfast->next;            Pslow = Pslow->next;        }//end while;        if(Pslow == head && i< k+1)            return head;        h = Pslow->next;        Pslow->next = NULL;        Pslow = h;        while(Pslow && Pslow->next)            Pslow = Pslow->next;               Pslow->next = head;      return h;            }//end func};

 

聯繫我們

該頁面正文內容均來源於網絡整理,並不代表阿里雲官方的觀點,該頁面所提到的產品和服務也與阿里云無關,如果該頁面內容對您造成了困擾,歡迎寫郵件給我們,收到郵件我們將在5個工作日內處理。

如果您發現本社區中有涉嫌抄襲的內容,歡迎發送郵件至: info-contact@alibabacloud.com 進行舉報並提供相關證據,工作人員會在 5 個工作天內聯絡您,一經查實,本站將立刻刪除涉嫌侵權內容。

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.