LeetCode題解：Triangle_leetcode

Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.

For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).

題意：給定一個數組代表一個三角形，找出其中和最小的路徑

解決思路：類似dfs的思路

代碼：

public class Solution {    public int minimumTotal(List<List<Integer>> triangle) {        if(triangle.size() == 0){            return 0;        }        for(int i = triangle.size() - 2; i >= 0; --i){            for(int j = 0; j <= i; ++j){                List<Integer> next = triangle.get(i + 1);                int sum = Math.min(next.get(j), next.get(j + 1)) + triangle.get(i).get(j);                triangle.get(i).set(j, sum);            }        }        return triangle.get(0).get(0);    }}