LeetCode Valid Palindrome

來源:互聯網
上載者:User

標籤:leetcode   字串   string   演算法   


Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.


先預先處理一下,轉化成所需要的類型,只要用簡單的迴文判斷方法就完了。


class Solution {public:    bool isPalindrome(string s) {        if(s.size()==0) return true;        char *str=new char [s.size()];        int k=0;        for(int i=0;i<s.size();i++){        if(s[i]>='a'&&s[i]<='z') str[k++]=s[i];        }        str[k]='\0';        int st=0,ed=k;        while(str[st++]==str[ed--]&&str<ed);        delete []str;        if(st>=ed) return true;        else return false;    }};


聯繫我們

該頁面正文內容均來源於網絡整理,並不代表阿里雲官方的觀點,該頁面所提到的產品和服務也與阿里云無關,如果該頁面內容對您造成了困擾,歡迎寫郵件給我們,收到郵件我們將在5個工作日內處理。

如果您發現本社區中有涉嫌抄襲的內容,歡迎發送郵件至: info-contact@alibabacloud.com 進行舉報並提供相關證據,工作人員會在 5 個工作天內聯絡您,一經查實,本站將立刻刪除涉嫌侵權內容。

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.