64. Minimum Path Sum (Graph; DP)

標籤：

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.

class Solution {public:    int minPathSum(vector<vector<int>> &grid) {        if(grid.empty()) return 0;                 vector<vector<int>> dp(grid.size(), vector<int>(grid[0].size(), 0));         dp[0][0] = grid[0][0];        for(int i = 1; i< grid[0].size(); i++)        {            dp[0][i] = dp[0][i-1] + grid[0][i];        }        for(int i = 1; i< grid.size(); i++)        {            dp[i][0] = dp[i-1][0] + grid[i][0];        }                for(int i = 1;i<grid.size(); i++)        {            for(int j = 1; j< grid[0].size(); j++)            {                dp[i][j] = min(dp[i-1][j], dp[i][j-1]) + grid[i][j];            }        }        return dp[grid.size()-1][grid[0].size()-1];    }};

 

64. Minimum Path Sum (Graph; DP)