版主 sqlsrv 自個兒弄的簡單類還需要您的協助

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上載者:User
版主 sqlsrv 自己弄的簡單類還需要您的協助

class DB_sqlsrv
{
var $query;
var $result;
function DB_sqlsrv($text)
{

$serverName = "192.168.0.1";
$connectionInfo = array(
"UID"=>"sa",
"PWD"=>"sa",
"Database"=>"ttt"
$conn = sqlsrv_connect( $serverName, $connectionInfo);
$this->query=sqlsrv_query($conn, $text);
}
//以對象形式取得查詢結果資料
function Record()
{
$this->result=sqlsrv_fetch_object($this->query);
return ($this->result)?($this->result):false;
}
}
$sql=new DB_sqlsrv("select * from username");
$record=$sql->Record();


出錯 PHP Warning: sqlsrv_fetch_object(): 2 is not a valid ss_sqlsrv_stmt resource in E:\web\test\test\test.php on line 20
$this->result=sqlsrv_fetch_object($this->query);
這句有問題,我看看類好像沒有問題的。請教謝謝。
------解決思路----------------------
$this->query=sqlsrv_query($conn, $text);
執行失敗

你 var_dump($this->query); 看看是什麼
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